3.7.63 \(\int \frac {(a+b x)^2}{x^{2/3}} \, dx\) [663]
Optimal. Leaf size=34 \[ 3 a^2 \sqrt [3]{x}+\frac {3}{2} a b x^{4/3}+\frac {3}{7} b^2 x^{7/3} \]
[Out]
3*a^2*x^(1/3)+3/2*a*b*x^(4/3)+3/7*b^2*x^(7/3)
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Rubi [A]
time = 0.01, antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps
used = 2, number of rules used = 1, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {45}
\begin {gather*} 3 a^2 \sqrt [3]{x}+\frac {3}{2} a b x^{4/3}+\frac {3}{7} b^2 x^{7/3} \end {gather*}
Antiderivative was successfully verified.
[In]
Int[(a + b*x)^2/x^(2/3),x]
[Out]
3*a^2*x^(1/3) + (3*a*b*x^(4/3))/2 + (3*b^2*x^(7/3))/7
Rule 45
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])
Rubi steps
\begin {align*} \int \frac {(a+b x)^2}{x^{2/3}} \, dx &=\int \left (\frac {a^2}{x^{2/3}}+2 a b \sqrt [3]{x}+b^2 x^{4/3}\right ) \, dx\\ &=3 a^2 \sqrt [3]{x}+\frac {3}{2} a b x^{4/3}+\frac {3}{7} b^2 x^{7/3}\\ \end {align*}
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Mathematica [A]
time = 0.01, size = 28, normalized size = 0.82 \begin {gather*} \frac {3}{14} \sqrt [3]{x} \left (14 a^2+7 a b x+2 b^2 x^2\right ) \end {gather*}
Antiderivative was successfully verified.
[In]
Integrate[(a + b*x)^2/x^(2/3),x]
[Out]
(3*x^(1/3)*(14*a^2 + 7*a*b*x + 2*b^2*x^2))/14
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Maple [A]
time = 0.11, size = 25, normalized size = 0.74
| | |
| method |
result |
size |
| | |
| trager |
\(\left (\frac {3}{7} x^{2} b^{2}+\frac {3}{2} a b x +3 a^{2}\right ) x^{\frac {1}{3}}\) |
\(24\) |
| gosper |
\(\frac {3 x^{\frac {1}{3}} \left (2 x^{2} b^{2}+7 a b x +14 a^{2}\right )}{14}\) |
\(25\) |
| derivativedivides |
\(3 a^{2} x^{\frac {1}{3}}+\frac {3 a b \,x^{\frac {4}{3}}}{2}+\frac {3 b^{2} x^{\frac {7}{3}}}{7}\) |
\(25\) |
| default |
\(3 a^{2} x^{\frac {1}{3}}+\frac {3 a b \,x^{\frac {4}{3}}}{2}+\frac {3 b^{2} x^{\frac {7}{3}}}{7}\) |
\(25\) |
| risch |
\(\frac {3 x^{\frac {1}{3}} \left (2 x^{2} b^{2}+7 a b x +14 a^{2}\right )}{14}\) |
\(25\) |
| | |
|
|
|
|
Verification of antiderivative is not currently implemented for this CAS.
[In]
int((b*x+a)^2/x^(2/3),x,method=_RETURNVERBOSE)
[Out]
3*a^2*x^(1/3)+3/2*a*b*x^(4/3)+3/7*b^2*x^(7/3)
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Maxima [A]
time = 0.26, size = 24, normalized size = 0.71 \begin {gather*} \frac {3}{7} \, b^{2} x^{\frac {7}{3}} + \frac {3}{2} \, a b x^{\frac {4}{3}} + 3 \, a^{2} x^{\frac {1}{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate((b*x+a)^2/x^(2/3),x, algorithm="maxima")
[Out]
3/7*b^2*x^(7/3) + 3/2*a*b*x^(4/3) + 3*a^2*x^(1/3)
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Fricas [A]
time = 0.96, size = 24, normalized size = 0.71 \begin {gather*} \frac {3}{14} \, {\left (2 \, b^{2} x^{2} + 7 \, a b x + 14 \, a^{2}\right )} x^{\frac {1}{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate((b*x+a)^2/x^(2/3),x, algorithm="fricas")
[Out]
3/14*(2*b^2*x^2 + 7*a*b*x + 14*a^2)*x^(1/3)
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Sympy [C] Result contains complex when optimal does not.
time = 0.98, size = 1741, normalized size = 51.21 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate((b*x+a)**2/x**(2/3),x)
[Out]
Piecewise((-27*a**(31/3)*(-1 + b*(a/b + x)/a)**(1/3)/(-14*a**8*b**(1/3) + 42*a**7*b**(4/3)*(a/b + x) - 42*a**6
*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) + 27*a**(31/3)*exp(I*pi/3)/(-14*a**8*b**(1/3) + 42*a*
*7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) + 72*a**(28/3)*b*(-1 +
b*(a/b + x)/a)**(1/3)*(a/b + x)/(-14*a**8*b**(1/3) + 42*a**7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)*
*2 + 14*a**5*b**(10/3)*(a/b + x)**3) - 81*a**(28/3)*b*(a/b + x)*exp(I*pi/3)/(-14*a**8*b**(1/3) + 42*a**7*b**(4
/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) - 60*a**(25/3)*b**2*(-1 + b*(a
/b + x)/a)**(1/3)*(a/b + x)**2/(-14*a**8*b**(1/3) + 42*a**7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2
+ 14*a**5*b**(10/3)*(a/b + x)**3) + 81*a**(25/3)*b**2*(a/b + x)**2*exp(I*pi/3)/(-14*a**8*b**(1/3) + 42*a**7*b
**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) + 18*a**(22/3)*b**3*(-1 +
b*(a/b + x)/a)**(1/3)*(a/b + x)**3/(-14*a**8*b**(1/3) + 42*a**7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x
)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) - 27*a**(22/3)*b**3*(a/b + x)**3*exp(I*pi/3)/(-14*a**8*b**(1/3) + 42*a*
*7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) - 9*a**(19/3)*b**4*(-1
+ b*(a/b + x)/a)**(1/3)*(a/b + x)**4/(-14*a**8*b**(1/3) + 42*a**7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b
+ x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) + 6*a**(16/3)*b**5*(-1 + b*(a/b + x)/a)**(1/3)*(a/b + x)**5/(-14*a**
8*b**(1/3) + 42*a**7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3), Abs
(b*(a/b + x)/a) > 1), (-27*a**(31/3)*(1 - b*(a/b + x)/a)**(1/3)*exp(I*pi/3)/(-14*a**8*b**(1/3) + 42*a**7*b**(4
/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) + 27*a**(31/3)*exp(I*pi/3)/(-1
4*a**8*b**(1/3) + 42*a**7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3)
+ 72*a**(28/3)*b*(1 - b*(a/b + x)/a)**(1/3)*(a/b + x)*exp(I*pi/3)/(-14*a**8*b**(1/3) + 42*a**7*b**(4/3)*(a/b
+ x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) - 81*a**(28/3)*b*(a/b + x)*exp(I*pi/3)/
(-14*a**8*b**(1/3) + 42*a**7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)*
*3) - 60*a**(25/3)*b**2*(1 - b*(a/b + x)/a)**(1/3)*(a/b + x)**2*exp(I*pi/3)/(-14*a**8*b**(1/3) + 42*a**7*b**(4
/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) + 81*a**(25/3)*b**2*(a/b + x)*
*2*exp(I*pi/3)/(-14*a**8*b**(1/3) + 42*a**7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(1
0/3)*(a/b + x)**3) + 18*a**(22/3)*b**3*(1 - b*(a/b + x)/a)**(1/3)*(a/b + x)**3*exp(I*pi/3)/(-14*a**8*b**(1/3)
+ 42*a**7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) - 27*a**(22/3)*
b**3*(a/b + x)**3*exp(I*pi/3)/(-14*a**8*b**(1/3) + 42*a**7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2
+ 14*a**5*b**(10/3)*(a/b + x)**3) - 9*a**(19/3)*b**4*(1 - b*(a/b + x)/a)**(1/3)*(a/b + x)**4*exp(I*pi/3)/(-14*
a**8*b**(1/3) + 42*a**7*b**(4/3)*(a/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3) +
6*a**(16/3)*b**5*(1 - b*(a/b + x)/a)**(1/3)*(a/b + x)**5*exp(I*pi/3)/(-14*a**8*b**(1/3) + 42*a**7*b**(4/3)*(a
/b + x) - 42*a**6*b**(7/3)*(a/b + x)**2 + 14*a**5*b**(10/3)*(a/b + x)**3), True))
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Giac [A]
time = 1.72, size = 24, normalized size = 0.71 \begin {gather*} \frac {3}{7} \, b^{2} x^{\frac {7}{3}} + \frac {3}{2} \, a b x^{\frac {4}{3}} + 3 \, a^{2} x^{\frac {1}{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate((b*x+a)^2/x^(2/3),x, algorithm="giac")
[Out]
3/7*b^2*x^(7/3) + 3/2*a*b*x^(4/3) + 3*a^2*x^(1/3)
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Mupad [B]
time = 0.03, size = 24, normalized size = 0.71 \begin {gather*} \frac {3\,x^{1/3}\,\left (14\,a^2+7\,a\,b\,x+2\,b^2\,x^2\right )}{14} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
int((a + b*x)^2/x^(2/3),x)
[Out]
(3*x^(1/3)*(14*a^2 + 2*b^2*x^2 + 7*a*b*x))/14
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